Gelöste Aufgaben/StaF

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Aufgabenstellung

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Lösung mit Maxima

Lorem Ipsum ....

(2A2Eη300(2A2Eη02)0A2Eη3000002A2Eη30(A2Eη402)(3A2Eη402)A2Eη60(A2Eη202)0A2Eη60(2A2Eη02)(A2Eη402)A2Eη+302AE203+8A2Eη030(2A2Eη02)(A2Eη+302AE403)3A2Eη302AE403A2Eη4020(3A2Eη402)03A2Eη+02AE203+2AE0(3A2Eη202)3A2Eη302AE403(3A2Eη+02AE403)(3A2Eη402)A2Eη30A2Eη60(2A2Eη02)(3A2Eη202)4A2Eη30(A2Eη402)3A2Eη402A2Eη600(A2Eη202)(A2Eη+302AE403)3A2Eη302AE403(A2Eη402)A2Eη+302AE403+A2Eη03(3A2Eη302AE403)(3A2Eη402)003A2Eη302AE403(3A2Eη+02AE403)3A2Eη402(3A2Eη302AE403)3A2Eη+02AE403+AE03A2Eη4020A2Eη60A2Eη402(3A2Eη402)A2Eη60(3A2Eη402)3A2Eη4022A2Eη30)(W1,0U1,0Φ1,0W2,0U2,0Φ2,0W3,0U3,0Φ3,0W4,0U4,0Φ4,0)=(00000F00)

Hier kommt jetzt irgendein Text.

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Element-Steigigkeitsmatrizen mit globalen Koordinaten
Element #1

k1=(8A2Eη0302A2Eη02(8A2Eη03)02A2Eη0202AE000(2AE0)02A2Eη0202A2Eη30(2A2Eη02)0A2Eη30(8A2Eη03)0(2A2Eη02)8A2Eη030(2A2Eη02)0(2AE0)002AE002A2Eη020A2Eη30(2A2Eη02)02A2Eη30)

Element #2

k2=(A2Eη+302AE4033A2Eη302AE403A2Eη402(A2Eη+302AE403)(3A2Eη302AE403)A2Eη4023A2Eη302AE4033A2Eη+02AE4033A2Eη402(3A2Eη302AE403)(3A2Eη+02AE403)3A2Eη402A2Eη4023A2Eη402A2Eη30(A2Eη402)(3A2Eη402)A2Eη60(A2Eη+302AE403)(3A2Eη302AE403)(A2Eη402)A2Eη+302AE4033A2Eη302AE403(A2Eη402)(3A2Eη302AE403)(3A2Eη+02AE403)(3A2Eη402)3A2Eη302AE4033A2Eη+02AE403(3A2Eη402)A2Eη4023A2Eη402A2Eη60(A2Eη402)(3A2Eη402)A2Eη30)

Element #3

k3=(A2Eη+302AE403(3A2Eη302AE403)A2Eη402(A2Eη+302AE403)3A2Eη302AE403A2Eη402(3A2Eη302AE403)3A2Eη+02AE403(3A2Eη402)3A2Eη302AE403(3A2Eη+02AE403)(3A2Eη402)A2Eη402(3A2Eη402)A2Eη30(A2Eη402)3A2Eη402A2Eη60(A2Eη+302AE403)3A2Eη302AE403(A2Eη402)A2Eη+302AE403(3A2Eη302AE403)(A2Eη402)3A2Eη302AE403(3A2Eη+02AE403)3A2Eη402(3A2Eη302AE403)3A2Eη+02AE4033A2Eη402A2Eη402(3A2Eη402)A2Eη60(A2Eη402)3A2Eη402A2Eη30)

Element #4

k4=(A2Eη030A2Eη202(A2Eη03)0A2Eη2020AE000(AE0)0A2Eη2020A2Eη30(A2Eη202)0A2Eη60(A2Eη03)0(A2Eη202)A2Eη030(A2Eη202)0(AE0)00AE00A2Eη2020A2Eη60(A2Eη202)0A2Eη30)


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