Gelöste Aufgaben/StaF

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Aufgabenstellung

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Caption

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Lösung mit Maxima

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(2A2Eη3ℓ00−(2A2Eηℓ02)0A2Eη3ℓ000002A2Eη3ℓ0−(A2Eη4ℓ02)−(3A2Eη4ℓ02)A2Eη6ℓ0−(A2Eη2ℓ02)0A2Eη6ℓ0−(2A2Eηℓ02)−(A2Eη4ℓ02)A2Eη+3ℓ02AE2ℓ03+8A2Eηℓ030−(2A2Eηℓ02)−(A2Eη+3ℓ02AE4ℓ03)3A2Eη−3ℓ02AE4ℓ03A2Eη4ℓ020−(3A2Eη4ℓ02)03A2Eη+ℓ02AE2ℓ03+2AEℓ0−(3A2Eη2ℓ02)3A2Eη−3ℓ02AE4ℓ03−(3A2Eη+ℓ02AE4ℓ03)−(3A2Eη4ℓ02)A2Eη3ℓ0A2Eη6ℓ0−(2A2Eηℓ02)−(3A2Eη2ℓ02)4A2Eη3ℓ0−(A2Eη4ℓ02)3A2Eη4ℓ02A2Eη6ℓ00−(A2Eη2ℓ02)−(A2Eη+3ℓ02AE4ℓ03)3A2Eη−3ℓ02AE4ℓ03−(A2Eη4ℓ02)A2Eη+3ℓ02AE4ℓ03+A2Eηℓ03−(3A2Eη−3ℓ02AE4ℓ03)−(3A2Eη4ℓ02)003A2Eη−3ℓ02AE4ℓ03−(3A2Eη+ℓ02AE4ℓ03)3A2Eη4ℓ02−(3A2Eη−3ℓ02AE4ℓ03)3A2Eη+ℓ02AE4ℓ03+AEℓ03A2Eη4ℓ020A2Eη6ℓ0A2Eη4ℓ02−(3A2Eη4ℓ02)A2Eη6ℓ0−(3A2Eη4ℓ02)3A2Eη4ℓ022A2Eη3ℓ0)⋅(W1,0U1,0Φ1,0W2,0U2,0Φ2,0W3,0U3,0Φ3,0W4,0U4,0Φ4,0)=(00000F00)

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