Zeile 1:
Zeile 1:
[[Category:Gelöste Aufgaben]]
[[index.php?title=Kategorie :Gelöste Aufgaben]]
[[Category:A*x=b]]
[[index.php?title=Kategorie :A*x=b]]
[[Category:Lineare Algebra]]
[[index.php?title=Kategorie :Lineare Algebra]]
[[Category:Numerische Lösung]]
[[index.php?title=Kategorie :Numerische Lösung]]
[[Category:Randwertproblem]]
[[index.php?title=Kategorie :Randwertproblem]]
[[Category:Prinzip der virtuellen Verrückungen]]
[[index.php?title=Kategorie :Prinzip der virtuellen Verrückungen]]
[[Category:Stab]][[Category:Dehnstab]]
[[index.php?title=Kategorie :Stab]][[index.php?title=Kategorie :Dehnstab]]
[[Category:Euler-Bernoulli-Balken]]
[[index.php?title=Kategorie :Euler-Bernoulli-Balken]]
[[Category:Finite-Elemente-Methode]]
[[index.php?title=Kategorie :Finite-Elemente-Methode ]]
[[Category:Maxima]]
[[index.php?title=Kategorie :Maxima ]]
[[Category:Stabwerk]]
[[index.php?title=Kategorie :Stabwerk]]
==Aufgabenstellung==
==Aufgabenstellung==
Zeile 28:
Zeile 28:
===Gleichgewichtsbedingungen===
===Gleichgewichtsbedingungen===
Für die Gleichgewichtsbedingung nach dem
Für die Gleichgewichtsbedingung nach dem [https://numpedia.rzbt.haw-hamburg.de/index.php?title=Werkzeuge/Gleichgewichtsbedingungen/Arbeitsprinzipe_der_Analytischen_Mechanik/Prinzip_der_virtuellen_Verr%C3%BCckungen Prinzip der virtuellen Verrückungen] ist
Delta W = 0
W = 0
= delta \Pi - \delta Wa
= delta \Pi - \delta Wa
benötigen wir die virtuelle Formänderungsenergie \delta \Pi und die virtuelle Arbeit der äußeren Kraft F.
benötigen wir die virtuelle Formänderungsenergie \delta \Pi und die virtuelle Arbeit der äußeren Kraft F.
Version vom 21. Oktober 2024, 19:20 Uhr
index.php?title=Kategorie:Gelöste Aufgaben
index.php?title=Kategorie:A*x=b
index.php?title=Kategorie:Lineare Algebra
index.php?title=Kategorie:Numerische Lösung
index.php?title=Kategorie:Randwertproblem
index.php?title=Kategorie:Prinzip der virtuellen Verrückungen
index.php?title=Kategorie:Stab index.php?title=Kategorie:Dehnstab
index.php?title=Kategorie:Euler-Bernoulli-Balken
index.php?title=Kategorie:Finite-Elemente-Methode
index.php?title=Kategorie:Maxima
index.php?title=Kategorie:Stabwerk
Aufgabenstellung
Wir untersuchen die Belastung eines ebenen Stabwerks. Die Stäbe haben wie skizziert die Länge ℓ bzw. ℓ/2.
Die Struktur wird mit der Kraft F belastet.
Caption
Gesucht ist ein Vergleich zwischen der klassischen Stabwerkstheorie und einer Herangehensweise, bei der wir eine feste Verbindung der Stäbe in den Knoten ansetzten. Grundlage des Modells ist die FEM-Lösung der Felddifferentialgleichung im Vergleich zur Lösung in Problemstellung „Stab“.
Wir stellen das Modell des Stabwerks mit dem Prinzip der virtuellen Verrückungen auf und vergleichen, wie sich diese von der Herangehensweise aus „Stab“ mit der analytischen Lösung unterscheidet.
Lösung mit Maxima
Wir nutzen das Computer-Algebra-System Maxima zur Lösung. Das macht hier Sinn, weil wir die Herangehensweise mit der aus Stab vergleichen wollen – für die wir ebenfalls Maxima eingesetzt haben.
Declarations
Wir übernehmen alle Vereinbarungen und Parameter aus der Problemformulierung „Stab“.
Gleichgewichtsbedingungen
Für die Gleichgewichtsbedingung nach dem Prinzip der virtuellen Verrückungen ist
W = 0
= delta \Pi - \delta Wa
benötigen wir die virtuelle Formänderungsenergie \delta \Pi und die virtuelle Arbeit der äußeren Kraft F.
Mit allen Konventionen für die Knoten-Verschiebungen ist
Delta Wa = -delta W_{4,0} *F
Für \delta \Pi gilt
(
2
A
2
E
η
3
ℓ
0
0
−
(
2
A
2
E
η
ℓ
0
2
)
0
A
2
E
η
3
ℓ
0
0
0
0
0
2
A
2
E
η
3
ℓ
0
−
(
A
2
E
η
4
ℓ
0
2
)
−
(
3
A
2
E
η
4
ℓ
0
2
)
A
2
E
η
6
ℓ
0
−
(
A
2
E
η
2
ℓ
0
2
)
0
A
2
E
η
6
ℓ
0
−
(
2
A
2
E
η
ℓ
0
2
)
−
(
A
2
E
η
4
ℓ
0
2
)
A
2
E
η
+
3
ℓ
0
2
A
E
2
ℓ
0
3
+
8
A
2
E
η
ℓ
0
3
0
−
(
2
A
2
E
η
ℓ
0
2
)
−
(
A
2
E
η
+
3
ℓ
0
2
A
E
4
ℓ
0
3
)
3
A
2
E
η
−
3
ℓ
0
2
A
E
4
ℓ
0
3
A
2
E
η
4
ℓ
0
2
0
−
(
3
A
2
E
η
4
ℓ
0
2
)
0
3
A
2
E
η
+
ℓ
0
2
A
E
2
ℓ
0
3
+
2
A
E
ℓ
0
−
(
3
A
2
E
η
2
ℓ
0
2
)
3
A
2
E
η
−
3
ℓ
0
2
A
E
4
ℓ
0
3
−
(
3
A
2
E
η
+
ℓ
0
2
A
E
4
ℓ
0
3
)
−
(
3
A
2
E
η
4
ℓ
0
2
)
A
2
E
η
3
ℓ
0
A
2
E
η
6
ℓ
0
−
(
2
A
2
E
η
ℓ
0
2
)
−
(
3
A
2
E
η
2
ℓ
0
2
)
4
A
2
E
η
3
ℓ
0
−
(
A
2
E
η
4
ℓ
0
2
)
3
A
2
E
η
4
ℓ
0
2
A
2
E
η
6
ℓ
0
0
−
(
A
2
E
η
2
ℓ
0
2
)
−
(
A
2
E
η
+
3
ℓ
0
2
A
E
4
ℓ
0
3
)
3
A
2
E
η
−
3
ℓ
0
2
A
E
4
ℓ
0
3
−
(
A
2
E
η
4
ℓ
0
2
)
A
2
E
η
+
3
ℓ
0
2
A
E
4
ℓ
0
3
+
A
2
E
η
ℓ
0
3
−
(
3
A
2
E
η
−
3
ℓ
0
2
A
E
4
ℓ
0
3
)
−
(
3
A
2
E
η
4
ℓ
0
2
)
0
0
3
A
2
E
η
−
3
ℓ
0
2
A
E
4
ℓ
0
3
−
(
3
A
2
E
η
+
ℓ
0
2
A
E
4
ℓ
0
3
)
3
A
2
E
η
4
ℓ
0
2
−
(
3
A
2
E
η
−
3
ℓ
0
2
A
E
4
ℓ
0
3
)
3
A
2
E
η
+
ℓ
0
2
A
E
4
ℓ
0
3
+
A
E
ℓ
0
3
A
2
E
η
4
ℓ
0
2
0
A
2
E
η
6
ℓ
0
A
2
E
η
4
ℓ
0
2
−
(
3
A
2
E
η
4
ℓ
0
2
)
A
2
E
η
6
ℓ
0
−
(
3
A
2
E
η
4
ℓ
0
2
)
3
A
2
E
η
4
ℓ
0
2
2
A
2
E
η
3
ℓ
0
)
⋅
(
W
1
,
0
U
1
,
0
Φ
1
,
0
W
2
,
0
U
2
,
0
Φ
2
,
0
W
3
,
0
U
3
,
0
Φ
3
,
0
W
4
,
0
U
4
,
0
Φ
4
,
0
)
=
(
0
0
0
0
0
F
0
0
)
{\displaystyle {\begin{pmatrix}{\frac {2{{A}^{2}}E\eta }{3{\ell _{0}}}}&0&-\left({\frac {2{{A}^{2}}E\eta }{{\ell }_{0}^{2}}}\right)&0&{\frac {{{A}^{2}}E\eta }{3{\ell _{0}}}}&0&0&0\\0&{\frac {2{{A}^{2}}E\eta }{3{\ell _{0}}}}&-\left({\frac {{{A}^{2}}E\eta }{4{{\ell }_{0}^{2}}}}\right)&-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{{\ell }_{0}^{2}}}}\right)&{\frac {{{A}^{2}}E\eta }{6{\ell _{0}}}}&-\left({\frac {{{A}^{2}}E\eta }{2{{\ell }_{0}^{2}}}}\right)&0&{\frac {{{A}^{2}}E\eta }{6{\ell _{0}}}}\\-\left({\frac {2{{A}^{2}}E\eta }{{\ell }_{0}^{2}}}\right)&-\left({\frac {{{A}^{2}}E\eta }{4{{\ell }_{0}^{2}}}}\right)&{\frac {{{A}^{2}}E\eta +3{{\ell }_{0}^{2}}AE}{2{{\ell }_{0}^{3}}}}+{\frac {8{{A}^{2}}E\eta }{{\ell }_{0}^{3}}}&0&-\left({\frac {2{{A}^{2}}E\eta }{{\ell }_{0}^{2}}}\right)&-\left({\frac {{{A}^{2}}E\eta +3{{\ell }_{0}^{2}}AE}{4{{\ell }_{0}^{3}}}}\right)&{\frac {{\sqrt {3}}{{A}^{2}}E\eta -{\sqrt {3}}{{\ell }_{0}^{2}}AE}{4{{\ell }_{0}^{3}}}}&{\frac {{{A}^{2}}E\eta }{4{{\ell }_{0}^{2}}}}\\0&-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{{\ell }_{0}^{2}}}}\right)&0&{\frac {3{{A}^{2}}E\eta +{{\ell }_{0}^{2}}AE}{2{{\ell }_{0}^{3}}}}+{\frac {2AE}{\ell _{0}}}&-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta }{2{{\ell }_{0}^{2}}}}\right)&{\frac {{\sqrt {3}}{{A}^{2}}E\eta -{\sqrt {3}}{{\ell }_{0}^{2}}AE}{4{{\ell }_{0}^{3}}}}&-\left({\frac {3{{A}^{2}}E\eta +{{\ell }_{0}^{2}}AE}{4{{\ell }_{0}^{3}}}}\right)&-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{{\ell }_{0}^{2}}}}\right)\\{\frac {{{A}^{2}}E\eta }{3{\ell _{0}}}}&{\frac {{{A}^{2}}E\eta }{6{\ell _{0}}}}&-\left({\frac {2{{A}^{2}}E\eta }{{\ell }_{0}^{2}}}\right)&-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta }{2{{\ell }_{0}^{2}}}}\right)&{\frac {4{{A}^{2}}E\eta }{3{\ell _{0}}}}&-\left({\frac {{{A}^{2}}E\eta }{4{{\ell }_{0}^{2}}}}\right)&{\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{{\ell }_{0}^{2}}}}&{\frac {{{A}^{2}}E\eta }{6{\ell _{0}}}}\\0&-\left({\frac {{{A}^{2}}E\eta }{2{{\ell }_{0}^{2}}}}\right)&-\left({\frac {{{A}^{2}}E\eta +3{{\ell }_{0}^{2}}AE}{4{{\ell }_{0}^{3}}}}\right)&{\frac {{\sqrt {3}}{{A}^{2}}E\eta -{\sqrt {3}}{{\ell }_{0}^{2}}AE}{4{{\ell }_{0}^{3}}}}&-\left({\frac {{{A}^{2}}E\eta }{4{{\ell }_{0}^{2}}}}\right)&{\frac {{{A}^{2}}E\eta +3{{\ell }_{0}^{2}}AE}{4{{\ell }_{0}^{3}}}}+{\frac {{{A}^{2}}E\eta }{{\ell }_{0}^{3}}}&-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta -{\sqrt {3}}{{\ell }_{0}^{2}}AE}{4{{\ell }_{0}^{3}}}}\right)&-\left({\frac {3{{A}^{2}}E\eta }{4{{\ell }_{0}^{2}}}}\right)\\0&0&{\frac {{\sqrt {3}}{{A}^{2}}E\eta -{\sqrt {3}}{{\ell }_{0}^{2}}AE}{4{{\ell }_{0}^{3}}}}&-\left({\frac {3{{A}^{2}}E\eta +{{\ell }_{0}^{2}}AE}{4{{\ell }_{0}^{3}}}}\right)&{\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{{\ell }_{0}^{2}}}}&-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta -{\sqrt {3}}{{\ell }_{0}^{2}}AE}{4{{\ell }_{0}^{3}}}}\right)&{\frac {3{{A}^{2}}E\eta +{{\ell }_{0}^{2}}AE}{4{{\ell }_{0}^{3}}}}+{\frac {AE}{\ell _{0}}}&{\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{{\ell }_{0}^{2}}}}\\0&{\frac {{{A}^{2}}E\eta }{6{\ell _{0}}}}&{\frac {{{A}^{2}}E\eta }{4{{\ell }_{0}^{2}}}}&-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{{\ell }_{0}^{2}}}}\right)&{\frac {{{A}^{2}}E\eta }{6{\ell _{0}}}}&-\left({\frac {3{{A}^{2}}E\eta }{4{{\ell }_{0}^{2}}}}\right)&{\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{{\ell }_{0}^{2}}}}&{\frac {2{{A}^{2}}E\eta }{3{\ell _{0}}}}\end{pmatrix}}\cdot {\begin{pmatrix}{W_{1,0}}\\{U_{1,0}}\\{{\Phi }_{1,0}}\\{W_{2,0}}\\{U_{2,0}}\\{{\Phi }_{2,0}}\\{W_{3,0}}\\{U_{3,0}}\\{{\Phi }_{3,0}}\\{W_{4,0}}\\{U_{4,0}}\\{{\Phi }_{4,0}}\end{pmatrix}}={\begin{pmatrix}0\\0\\0\\0\\0\\F\\0\\0\end{pmatrix}}}
Hier kommt jetzt irgendein Text.
S
o
m
e
T
e
x
t
{\displaystyle SomeText}
Title
Text
Element-Steigigkeitsmatrizen mit globalen Koordinaten
Element #1
k
1
=
(
8
A
2
E
η
ℓ
0
3
0
2
A
2
E
η
ℓ
0
2
−
(
8
A
2
E
η
ℓ
0
3
)
0
2
A
2
E
η
ℓ
0
2
0
2
A
E
ℓ
0
0
0
−
(
2
A
E
ℓ
0
)
0
2
A
2
E
η
ℓ
0
2
0
2
A
2
E
η
3
ℓ
0
−
(
2
A
2
E
η
ℓ
0
2
)
0
A
2
E
η
3
ℓ
0
−
(
8
A
2
E
η
ℓ
0
3
)
0
−
(
2
A
2
E
η
ℓ
0
2
)
8
A
2
E
η
ℓ
0
3
0
−
(
2
A
2
E
η
ℓ
0
2
)
0
−
(
2
A
E
ℓ
0
)
0
0
2
A
E
ℓ
0
0
2
A
2
E
η
ℓ
0
2
0
A
2
E
η
3
ℓ
0
−
(
2
A
2
E
η
ℓ
0
2
)
0
2
A
2
E
η
3
ℓ
0
)
{\displaystyle {k_{1}}={\begin{pmatrix}{\frac {8{{A}^{2}}E\eta }{\ell _{0}^{3}}}&0&{\frac {2{{A}^{2}}E\eta }{\ell _{0}^{2}}}&-\left({\frac {8{{A}^{2}}E\eta }{\ell _{0}^{3}}}\right)&0&{\frac {2{{A}^{2}}E\eta }{\ell _{0}^{2}}}\\0&{\frac {2AE}{\ell _{0}}}&0&0&-\left({\frac {2AE}{\ell _{0}}}\right)&0\\{\frac {2{{A}^{2}}E\eta }{\ell _{0}^{2}}}&0&{\frac {2{{A}^{2}}E\eta }{3{\ell _{0}}}}&-\left({\frac {2{{A}^{2}}E\eta }{\ell _{0}^{2}}}\right)&0&{\frac {{{A}^{2}}E\eta }{3{\ell _{0}}}}\\-\left({\frac {8{{A}^{2}}E\eta }{\ell _{0}^{3}}}\right)&0&-\left({\frac {2{{A}^{2}}E\eta }{\ell _{0}^{2}}}\right)&{\frac {8{{A}^{2}}E\eta }{\ell _{0}^{3}}}&0&-\left({\frac {2{{A}^{2}}E\eta }{\ell _{0}^{2}}}\right)\\0&-\left({\frac {2AE}{\ell _{0}}}\right)&0&0&{\frac {2AE}{\ell _{0}}}&0\\{\frac {2{{A}^{2}}E\eta }{\ell _{0}^{2}}}&0&{\frac {{{A}^{2}}E\eta }{3{\ell _{0}}}}&-\left({\frac {2{{A}^{2}}E\eta }{\ell _{0}^{2}}}\right)&0&{\frac {2{{A}^{2}}E\eta }{3{\ell _{0}}}}\end{pmatrix}}}
Element #2
k
2
=
(
A
2
E
η
+
3
ℓ
0
2
A
E
4
ℓ
0
3
3
A
2
E
η
−
3
ℓ
0
2
A
E
4
ℓ
0
3
A
2
E
η
4
ℓ
0
2
−
(
A
2
E
η
+
3
ℓ
0
2
A
E
4
ℓ
0
3
)
−
(
3
A
2
E
η
−
3
ℓ
0
2
A
E
4
ℓ
0
3
)
A
2
E
η
4
ℓ
0
2
3
A
2
E
η
−
3
ℓ
0
2
A
E
4
ℓ
0
3
3
A
2
E
η
+
ℓ
0
2
A
E
4
ℓ
0
3
3
A
2
E
η
4
ℓ
0
2
−
(
3
A
2
E
η
−
3
ℓ
0
2
A
E
4
ℓ
0
3
)
−
(
3
A
2
E
η
+
ℓ
0
2
A
E
4
ℓ
0
3
)
3
A
2
E
η
4
ℓ
0
2
A
2
E
η
4
ℓ
0
2
3
A
2
E
η
4
ℓ
0
2
A
2
E
η
3
ℓ
0
−
(
A
2
E
η
4
ℓ
0
2
)
−
(
3
A
2
E
η
4
ℓ
0
2
)
A
2
E
η
6
ℓ
0
−
(
A
2
E
η
+
3
ℓ
0
2
A
E
4
ℓ
0
3
)
−
(
3
A
2
E
η
−
3
ℓ
0
2
A
E
4
ℓ
0
3
)
−
(
A
2
E
η
4
ℓ
0
2
)
A
2
E
η
+
3
ℓ
0
2
A
E
4
ℓ
0
3
3
A
2
E
η
−
3
ℓ
0
2
A
E
4
ℓ
0
3
−
(
A
2
E
η
4
ℓ
0
2
)
−
(
3
A
2
E
η
−
3
ℓ
0
2
A
E
4
ℓ
0
3
)
−
(
3
A
2
E
η
+
ℓ
0
2
A
E
4
ℓ
0
3
)
−
(
3
A
2
E
η
4
ℓ
0
2
)
3
A
2
E
η
−
3
ℓ
0
2
A
E
4
ℓ
0
3
3
A
2
E
η
+
ℓ
0
2
A
E
4
ℓ
0
3
−
(
3
A
2
E
η
4
ℓ
0
2
)
A
2
E
η
4
ℓ
0
2
3
A
2
E
η
4
ℓ
0
2
A
2
E
η
6
ℓ
0
−
(
A
2
E
η
4
ℓ
0
2
)
−
(
3
A
2
E
η
4
ℓ
0
2
)
A
2
E
η
3
ℓ
0
)
{\displaystyle {k_{2}}={\begin{pmatrix}{\frac {{{A}^{2}}E\eta +3{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}&{\frac {{\sqrt {3}}{{A}^{2}}E\eta -{\sqrt {3}}{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}&{\frac {{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}&-\left({\frac {{{A}^{2}}E\eta +3{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}\right)&-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta -{\sqrt {3}}{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}\right)&{\frac {{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}\\{\frac {{\sqrt {3}}{{A}^{2}}E\eta -{\sqrt {3}}{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}&{\frac {3{{A}^{2}}E\eta +{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}&{\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}&-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta -{\sqrt {3}}{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}\right)&-\left({\frac {3{{A}^{2}}E\eta +{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}\right)&{\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}\\{\frac {{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}&{\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}&{\frac {{{A}^{2}}E\eta }{3{\ell _{0}}}}&-\left({\frac {{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}\right)&-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}\right)&{\frac {{{A}^{2}}E\eta }{6{\ell _{0}}}}\\-\left({\frac {{{A}^{2}}E\eta +3{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}\right)&-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta -{\sqrt {3}}{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}\right)&-\left({\frac {{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}\right)&{\frac {{{A}^{2}}E\eta +3{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}&{\frac {{\sqrt {3}}{{A}^{2}}E\eta -{\sqrt {3}}{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}&-\left({\frac {{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}\right)\\-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta -{\sqrt {3}}{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}\right)&-\left({\frac {3{{A}^{2}}E\eta +{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}\right)&-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}\right)&{\frac {{\sqrt {3}}{{A}^{2}}E\eta -{\sqrt {3}}{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}&{\frac {3{{A}^{2}}E\eta +{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}&-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}\right)\\{\frac {{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}&{\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}&{\frac {{{A}^{2}}E\eta }{6{\ell _{0}}}}&-\left({\frac {{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}\right)&-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}\right)&{\frac {{{A}^{2}}E\eta }{3{\ell _{0}}}}\end{pmatrix}}}
Element #3
k
3
=
(
A
2
E
η
+
3
ℓ
0
2
A
E
4
ℓ
0
3
−
(
3
A
2
E
η
−
3
ℓ
0
2
A
E
4
ℓ
0
3
)
A
2
E
η
4
ℓ
0
2
−
(
A
2
E
η
+
3
ℓ
0
2
A
E
4
ℓ
0
3
)
3
A
2
E
η
−
3
ℓ
0
2
A
E
4
ℓ
0
3
A
2
E
η
4
ℓ
0
2
−
(
3
A
2
E
η
−
3
ℓ
0
2
A
E
4
ℓ
0
3
)
3
A
2
E
η
+
ℓ
0
2
A
E
4
ℓ
0
3
−
(
3
A
2
E
η
4
ℓ
0
2
)
3
A
2
E
η
−
3
ℓ
0
2
A
E
4
ℓ
0
3
−
(
3
A
2
E
η
+
ℓ
0
2
A
E
4
ℓ
0
3
)
−
(
3
A
2
E
η
4
ℓ
0
2
)
A
2
E
η
4
ℓ
0
2
−
(
3
A
2
E
η
4
ℓ
0
2
)
A
2
E
η
3
ℓ
0
−
(
A
2
E
η
4
ℓ
0
2
)
3
A
2
E
η
4
ℓ
0
2
A
2
E
η
6
ℓ
0
−
(
A
2
E
η
+
3
ℓ
0
2
A
E
4
ℓ
0
3
)
3
A
2
E
η
−
3
ℓ
0
2
A
E
4
ℓ
0
3
−
(
A
2
E
η
4
ℓ
0
2
)
A
2
E
η
+
3
ℓ
0
2
A
E
4
ℓ
0
3
−
(
3
A
2
E
η
−
3
ℓ
0
2
A
E
4
ℓ
0
3
)
−
(
A
2
E
η
4
ℓ
0
2
)
3
A
2
E
η
−
3
ℓ
0
2
A
E
4
ℓ
0
3
−
(
3
A
2
E
η
+
ℓ
0
2
A
E
4
ℓ
0
3
)
3
A
2
E
η
4
ℓ
0
2
−
(
3
A
2
E
η
−
3
ℓ
0
2
A
E
4
ℓ
0
3
)
3
A
2
E
η
+
ℓ
0
2
A
E
4
ℓ
0
3
3
A
2
E
η
4
ℓ
0
2
A
2
E
η
4
ℓ
0
2
−
(
3
A
2
E
η
4
ℓ
0
2
)
A
2
E
η
6
ℓ
0
−
(
A
2
E
η
4
ℓ
0
2
)
3
A
2
E
η
4
ℓ
0
2
A
2
E
η
3
ℓ
0
)
{\displaystyle {k_{3}}={\begin{pmatrix}{\frac {{{A}^{2}}E\eta +3{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}&-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta -{\sqrt {3}}{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}\right)&{\frac {{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}&-\left({\frac {{{A}^{2}}E\eta +3{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}\right)&{\frac {{\sqrt {3}}{{A}^{2}}E\eta -{\sqrt {3}}{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}&{\frac {{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}\\-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta -{\sqrt {3}}{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}\right)&{\frac {3{{A}^{2}}E\eta +{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}&-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}\right)&{\frac {{\sqrt {3}}{{A}^{2}}E\eta -{\sqrt {3}}{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}&-\left({\frac {3{{A}^{2}}E\eta +{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}\right)&-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}\right)\\{\frac {{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}&-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}\right)&{\frac {{{A}^{2}}E\eta }{3{\ell _{0}}}}&-\left({\frac {{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}\right)&{\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}&{\frac {{{A}^{2}}E\eta }{6{\ell _{0}}}}\\-\left({\frac {{{A}^{2}}E\eta +3{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}\right)&{\frac {{\sqrt {3}}{{A}^{2}}E\eta -{\sqrt {3}}{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}&-\left({\frac {{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}\right)&{\frac {{{A}^{2}}E\eta +3{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}&-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta -{\sqrt {3}}{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}\right)&-\left({\frac {{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}\right)\\{\frac {{\sqrt {3}}{{A}^{2}}E\eta -{\sqrt {3}}{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}&-\left({\frac {3{{A}^{2}}E\eta +{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}\right)&{\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}&-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta -{\sqrt {3}}{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}\right)&{\frac {3{{A}^{2}}E\eta +{\ell _{0}^{2}}AE}{4{\ell _{0}^{3}}}}&{\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}\\{\frac {{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}&-\left({\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}\right)&{\frac {{{A}^{2}}E\eta }{6{\ell _{0}}}}&-\left({\frac {{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}\right)&{\frac {{\sqrt {3}}{{A}^{2}}E\eta }{4{\ell _{0}^{2}}}}&{\frac {{{A}^{2}}E\eta }{3{\ell _{0}}}}\end{pmatrix}}}
Element #4
k
4
=
(
A
2
E
η
ℓ
0
3
0
A
2
E
η
2
ℓ
0
2
−
(
A
2
E
η
ℓ
0
3
)
0
A
2
E
η
2
ℓ
0
2
0
A
E
ℓ
0
0
0
−
(
A
E
ℓ
0
)
0
A
2
E
η
2
ℓ
0
2
0
A
2
E
η
3
ℓ
0
−
(
A
2
E
η
2
ℓ
0
2
)
0
A
2
E
η
6
ℓ
0
−
(
A
2
E
η
ℓ
0
3
)
0
−
(
A
2
E
η
2
ℓ
0
2
)
A
2
E
η
ℓ
0
3
0
−
(
A
2
E
η
2
ℓ
0
2
)
0
−
(
A
E
ℓ
0
)
0
0
A
E
ℓ
0
0
A
2
E
η
2
ℓ
0
2
0
A
2
E
η
6
ℓ
0
−
(
A
2
E
η
2
ℓ
0
2
)
0
A
2
E
η
3
ℓ
0
)
{\displaystyle {k_{4}}={\begin{pmatrix}{\frac {{{A}^{2}}E\eta }{\ell _{0}^{3}}}&0&{\frac {{{A}^{2}}E\eta }{2{\ell _{0}^{2}}}}&-\left({\frac {{{A}^{2}}E\eta }{\ell _{0}^{3}}}\right)&0&{\frac {{{A}^{2}}E\eta }{2{\ell _{0}^{2}}}}\\0&{\frac {AE}{\ell _{0}}}&0&0&-\left({\frac {AE}{\ell _{0}}}\right)&0\\{\frac {{{A}^{2}}E\eta }{2{\ell _{0}^{2}}}}&0&{\frac {{{A}^{2}}E\eta }{3{\ell _{0}}}}&-\left({\frac {{{A}^{2}}E\eta }{2{\ell _{0}^{2}}}}\right)&0&{\frac {{{A}^{2}}E\eta }{6{\ell _{0}}}}\\-\left({\frac {{{A}^{2}}E\eta }{\ell _{0}^{3}}}\right)&0&-\left({\frac {{{A}^{2}}E\eta }{2{\ell _{0}^{2}}}}\right)&{\frac {{{A}^{2}}E\eta }{\ell _{0}^{3}}}&0&-\left({\frac {{{A}^{2}}E\eta }{2{\ell _{0}^{2}}}}\right)\\0&-\left({\frac {AE}{\ell _{0}}}\right)&0&0&{\frac {AE}{\ell _{0}}}&0\\{\frac {{{A}^{2}}E\eta }{2{\ell _{0}^{2}}}}&0&{\frac {{{A}^{2}}E\eta }{6{\ell _{0}}}}&-\left({\frac {{{A}^{2}}E\eta }{2{\ell _{0}^{2}}}}\right)&0&{\frac {{{A}^{2}}E\eta }{3{\ell _{0}}}}\end{pmatrix}}}
Links
Literature