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Zeile 110: Zeile 110:
0&0&0&0&0&0&\color{magenta}-K_S&\color{magenta}K_S\\
0&0&0&0&0&0&\color{magenta}-K_S&\color{magenta}K_S\\
\end{array} \right)</math>
\end{array} \right)</math>
::<math>
\underline{r}_{B,1}=\left(\begin{array}{c}
              H - h          - b \cdot \sin(\Phi_1(t))\\
              -v_0 t  + W_1(t) + b \cdot \cos(\Phi_1(t)) \end{array}\right)
</math>
::<math>
\underline{r}_{B,2}=\left(\begin{array}{c}
              H            - r_2 \cdot \cos(\Omega t+\Psi_2(t)+\Theta_2)\\
              -v_0 t + W_2(t)- r_2 \cdot \sin(\Omega t+\Psi_2(t)+\Theta_2)
                          \end{array}\right)
</math>
::<math>
\underline{r}_{A}=\left(\begin{array}{c}
              H              - R_1 \cdot \cos(\Omega t+\Psi_1(t)+\Theta_1)\\
              -v_0 t + W_1(t) - R_1 \cdot \sin(\Omega t+\Psi_1(t)+\Theta_1)                          \end{array}\right)
</math>
::<math>
\underline{v}_{B,rel}=
                        \underline{\dot{r}}_{B,1} -
                        \underline{\dot{r}}_{B,2}
</math>
::<math>\dot{\left(.\right)} := \frac{d (.)}{dt}</math>
::<math>\delta W^a = \delta W^a_{A} + \delta W^a_{B} + \delta W^a_{d'Alembert}</math>
::<math>
\delta r_{B,1}=\left(\begin{array}{c}
              -\delta \Phi_1 b\\
              \delta W_1
\end{array}\right)
</math>
::<math>
\delta r_{B2}=\left(\begin{array}{c}
          r_2 \cdot \delta \Psi_2 \sin(\psi)\\
          \delta W_2 - r_2 \cdot \delta \Psi_2 \cos(\psi)
\end{array}\right)
</math>
::<math>
\delta r_A=\left(\begin{array}{c}
          0\\
          \delta W_2 + R_1 \cdot \delta \Psi_1
\end{array}\right)
</math>
::<math>\delta W^a_{A} = </math>


==tmp==
==tmp==

Version vom 10. März 2025, 06:47 Uhr


Aufgabenstellung

SOME TEXT


Caption

Gesucht ist "SOME EXPLANATION"


Lösung mit Maxima

Lorem Ipsum ....

Q~_=(W0Φ0W1Φ1W2Φ2,Ψ1,Ψ2)
δQ~_=(δW0δΦ0δW1δΦ1δW2δΦ2,δΨ1,δΨ2)


Y_=[Q_Q˙_]
Y˙_=f_(Y_)=[Q˙_−M__−1⋅K__⋅Q_+M__−1⋅P_]
M__⋅Q¨_+K__⋅Q_=P_(Q_,Q˙_)
δW=δWa−δΠ=!0
δΠ=δΠG+δΠS
δΠS=KS⋅(Ψ2−Ψ1)⋅(δΨ2−δΨ1)
δΠG=δΠG1+δΠG2
δΠGi=∫0ℓiMi(x)⋅δwi″(x)dx
Mi(x)=E⋅I(x)⋅wi″(x)
wi(x)=Q_iT⋅φ_
φ_=[(ξ−1)2⋅(2⋅ξ+1)ℓi⋅ξ⋅(ξ−1)2−ξ2⋅(2ξ−3)ℓi⋅ξ2⋅(ξ−1)]
Q~_i=(Wi−1Φi−qWiΦi)
δΠGi=∫0ℓiE⋅Ii(x)⋅(Wi−1φ1⋅δWi−1φ1+Φi−1φ2⋅δWi−1φ1+Wiφ3⋅δWi−1φ1+…+Φiφ4⋅δΦiφ4)


δΠGi=δQiT⋅K__i⋅Qi
ki,jk=∫0ℓiE⋅Ii(x)φj⋅φkdx
Ii(x)=π64(Di(x)4−di(x)4)


Di(x)=Di−1⋅(ξ1−1)+Di⋅ξ1di(x)=di−1⋅(ξ1−1)+di⋅ξ1
ξ1=xℓ1
ξ2=(x−H)ℓ2


K__=(k1,11k1,12k1,13k1,140000k1,12k1,22k1,23k1,240000k1,13k1,23k1,33+k2,11k1,34+k2,12k2,13k2,1400k1,14k1,24k1,34+k2,12k1,44+k2,22k2,23k2,240000k2,13k2,23k2,33k2,340000k2,14k2,24k2,34k2,4400000000KS−KS000000−KSKS)


r_B,1=(H−h−b⋅sin⁡(Φ1(t))−v0t+W1(t)+b⋅cos⁡(Φ1(t)))
r_B,2=(H−r2⋅cos⁡(Ωt+Ψ2(t)+Θ2)−v0t+W2(t)−r2⋅sin⁡(Ωt+Ψ2(t)+Θ2))
r_A=(H−R1⋅cos⁡(Ωt+Ψ1(t)+Θ1)−v0t+W1(t)−R1⋅sin⁡(Ωt+Ψ1(t)+Θ1))


v_B,rel=r˙_B,1−r˙_B,2
(.)˙:=d(.)dt


δWa=δWAa+δWBa+δWd′Alemberta
δrB,1=(−δΦ1bδW1)
δrB2=(r2⋅δΨ2sin⁡(ψ)δW2−r2⋅δΨ2cos⁡(ψ))
δrA=(0δW2+R1⋅δΨ1)


δWAa=




tmp

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