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<table class="wikitable mw-collapsible" style="background-color:white; float: left; margin-right:14px;">
<table class="wikitable mw-collapsible" style="background-color:white; float: none; margin-right:14px;">
<tr><th></th><th></th></tr>
<tr><th>Element #1</th></tr>
<tr><td></td><td></td></tr>
<!------------------------------------------->
<tr><td>
<math>
{k_1} = \begin{pmatrix}\frac{8 {{A}^{2}} E \eta }{{\ell_{0}^{3}}} & 0 & \frac{2 {{A}^{2}} E \eta }{{\ell_{0}^{2}}} & -\left( \frac{8 {{A}^{2}} E \eta }{{\ell_{0}^{3}}}\right)  & 0 & \frac{2 {{A}^{2}} E \eta }{{\ell_{0}^{2}}}\\
0 & \frac{2 A E}{{\ell_0}} & 0 & 0 & -\left( \frac{2 A E}{{\ell_0}}\right)  & 0\\
\frac{2 {{A}^{2}} E \eta }{{\ell_{0}^{2}}} & 0 & \frac{2 {{A}^{2}} E \eta }{3 {\ell_0}} & -\left( \frac{2 {{A}^{2}} E \eta }{{\ell_{0}^{2}}}\right)  & 0 & \frac{{{A}^{2}} E \eta }{3 {\ell_0}}\\
-\left( \frac{8 {{A}^{2}} E \eta }{{\ell_{0}^{3}}}\right)  & 0 & -\left( \frac{2 {{A}^{2}} E \eta }{{\ell_{0}^{2}}}\right)  & \frac{8 {{A}^{2}} E \eta }{{\ell_{0}^{3}}} & 0 & -\left( \frac{2 {{A}^{2}} E \eta }{{\ell_{0}^{2}}}\right) \\
0 & -\left( \frac{2 A E}{{\ell_0}}\right)  & 0 & 0 & \frac{2 A E}{{\ell_0}} & 0\\
\frac{2 {{A}^{2}} E \eta }{{\ell_{0}^{2}}} & 0 & \frac{{{A}^{2}} E \eta }{3 {\ell_0}} & -\left( \frac{2 {{A}^{2}} E \eta }{{\ell_{0}^{2}}}\right)  & 0 & \frac{2 {{A}^{2}} E \eta }{3 {\ell_0}}\end{pmatrix}
</math>
</td></tr>
<tr><th>Element #2</th></tr>
<tr><td>
<math>
</math>
</td></tr>
<tr><th>Element #3</th></tr>
<tr><td>
<math>
</math>
</td></tr>
<tr><th>Element #1</th></tr>
<tr><td>
<math>
</math>
</td></tr>
</table>
</table>


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Version vom 21. Oktober 2024, 13:18 Uhr


Aufgabenstellung

SOME TEXT


Caption

Gesucht ist "SOME EXPLANATION"


Lösung mit Maxima

Lorem Ipsum ....

(2A2Eη3ℓ00−(2A2Eηℓ02)0A2Eη3ℓ000002A2Eη3ℓ0−(A2Eη4ℓ02)−(3A2Eη4ℓ02)A2Eη6ℓ0−(A2Eη2ℓ02)0A2Eη6ℓ0−(2A2Eηℓ02)−(A2Eη4ℓ02)A2Eη+3ℓ02AE2ℓ03+8A2Eηℓ030−(2A2Eηℓ02)−(A2Eη+3ℓ02AE4ℓ03)3A2Eη−3ℓ02AE4ℓ03A2Eη4ℓ020−(3A2Eη4ℓ02)03A2Eη+ℓ02AE2ℓ03+2AEℓ0−(3A2Eη2ℓ02)3A2Eη−3ℓ02AE4ℓ03−(3A2Eη+ℓ02AE4ℓ03)−(3A2Eη4ℓ02)A2Eη3ℓ0A2Eη6ℓ0−(2A2Eηℓ02)−(3A2Eη2ℓ02)4A2Eη3ℓ0−(A2Eη4ℓ02)3A2Eη4ℓ02A2Eη6ℓ00−(A2Eη2ℓ02)−(A2Eη+3ℓ02AE4ℓ03)3A2Eη−3ℓ02AE4ℓ03−(A2Eη4ℓ02)A2Eη+3ℓ02AE4ℓ03+A2Eηℓ03−(3A2Eη−3ℓ02AE4ℓ03)−(3A2Eη4ℓ02)003A2Eη−3ℓ02AE4ℓ03−(3A2Eη+ℓ02AE4ℓ03)3A2Eη4ℓ02−(3A2Eη−3ℓ02AE4ℓ03)3A2Eη+ℓ02AE4ℓ03+AEℓ03A2Eη4ℓ020A2Eη6ℓ0A2Eη4ℓ02−(3A2Eη4ℓ02)A2Eη6ℓ0−(3A2Eη4ℓ02)3A2Eη4ℓ022A2Eη3ℓ0)⋅(W1,0U1,0Φ1,0W2,0U2,0Φ2,0W3,0U3,0Φ3,0W4,0U4,0Φ4,0)=(00000F00)

Fehler beim Parsen (Syntaxfehler): {\displaystyle </math ==tmp== <!--------------------------------------------------------------------------------> {{MyCodeBlock|title=Title |text=Text |code= <syntaxhighlight lang="lisp" line start=1> 1+1 </syntaxhighlight> }} <table class="wikitable mw-collapsible" style="background-color:white; float: none; margin-right:14px;"> <tr><th>Element #1</th></tr> <!-------------------------------------------> <tr><td> <math> {k_1} = \begin{pmatrix}\frac{8 {{A}^{2}} E \eta }{{\ell_{0}^{3}}} & 0 & \frac{2 {{A}^{2}} E \eta }{{\ell_{0}^{2}}} & -\left( \frac{8 {{A}^{2}} E \eta }{{\ell_{0}^{3}}}\right) & 0 & \frac{2 {{A}^{2}} E \eta }{{\ell_{0}^{2}}}\\ 0 & \frac{2 A E}{{\ell_0}} & 0 & 0 & -\left( \frac{2 A E}{{\ell_0}}\right) & 0\\ \frac{2 {{A}^{2}} E \eta }{{\ell_{0}^{2}}} & 0 & \frac{2 {{A}^{2}} E \eta }{3 {\ell_0}} & -\left( \frac{2 {{A}^{2}} E \eta }{{\ell_{0}^{2}}}\right) & 0 & \frac{{{A}^{2}} E \eta }{3 {\ell_0}}\\ -\left( \frac{8 {{A}^{2}} E \eta }{{\ell_{0}^{3}}}\right) & 0 & -\left( \frac{2 {{A}^{2}} E \eta }{{\ell_{0}^{2}}}\right) & \frac{8 {{A}^{2}} E \eta }{{\ell_{0}^{3}}} & 0 & -\left( \frac{2 {{A}^{2}} E \eta }{{\ell_{0}^{2}}}\right) \\ 0 & -\left( \frac{2 A E}{{\ell_0}}\right) & 0 & 0 & \frac{2 A E}{{\ell_0}} & 0\\ \frac{2 {{A}^{2}} E \eta }{{\ell_{0}^{2}}} & 0 & \frac{{{A}^{2}} E \eta }{3 {\ell_0}} & -\left( \frac{2 {{A}^{2}} E \eta }{{\ell_{0}^{2}}}\right) & 0 & \frac{2 {{A}^{2}} E \eta }{3 {\ell_0}}\end{pmatrix} }

Element #2

Element #3

Element #1


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